Question

what is the slope-intercept form of the equation of the line that passes through the point (–6, 1) and is perpendicular to the graph of 2x 3y = –5?

Answer 1

d on ed

Explanation:

Answer 2

Line II
2x+3y=-5
3y=-2x-5
y=
`(-2)/(3) x- (5)/(3)`

Gradient m=
`(-2)/(3)`
Gradient of line I will be;

`(-2)/(3) *m=-1`
m=
`(3)/(2)`
Equation of line I;
y=mx+c
y=
`(3)/(2) x+c`
Finding value of c by replacing for;
y=1
x=-6
1=
`(3)/(2) *(-6)+c`
c=10
y=
`(3)/(2) x+10`