Question

Using the rules for special cases, what is the result of (-2x+2)^2

Answer 1

`(-2x+2)^2`
We know that:

`\left(a+b\right)^2=a^2+2ab+b^2`
So:

`=\left(-2x\right)^2+2\left(-2x\right)\cdot \:2+2^2`
Now:

`=\left(-2x\right)^2-2\cdot \:2x\cdot \:2+2^2`
We apply the law of exponents and solve, so we get:

`=4x^2-8x+4`