Question

Mischa wrote the quadratic equation 0 = –x2 + 4x – 7 in standard form. What is the value of c in her equation

Answer 1

Mischa wrote the quadratic equation 0 = –x2 + 4x – 7 in standard form

The standard form of quadratic equation is

`y= ax^2 + bx + c`

When y=0 then the standard equation becomes

`0= ax^2 + bx + c`

Now we compare the given equation
`0 = -x^2 + 4x - 7` with
`0= ax^2 + bx + c` and find the value of a, b,c

-x^2 can be written as -1x^2

`0= ax^2 + bx + c`

`0 = -1x^2 + 4x - 7`

a= -1 , b=4 and c=-7

The value of c is -7

Answer 2

Standard form for quadratic equations is:

ax² + bx + c = 0

Therefore, in Mischa's equation, the value of c is -7.