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If a ball dropped from a tower reaches the ground after 3.5 seconds, what is the height of the tower? Given: g = -9.8 meters/second2
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If a ball dropped from a tower reaches the ground after 3.5 seconds, what is the height of the tower? Given: g = -9.8 meters/second2
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Feb 1, 2017
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If a ball dropped from a tower reaches the ground after 3.5 seconds, what is the height of the tower? Given: g = -9.8 meters/second2
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Winky
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Answer:
60.03
Step-by-step explanation:
Plato answer! Just Took the test
Nicopuri
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Feb 3, 2017
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To find the height of the tower, a formula for free-fall motion can be used, especially since the time and the force of gravity are given. The formula is shown below:
h = (1/2)*g*t^2
Where:
h = height of the tower = ?
g = acceleration due to gravity = -9.8 m/s^2
t = time = 3.5 seconds
Substituting the given values:
h = (1/2)*(9.8)*(3.5)^2
h = 60.025 meters
Ipsit Gaur
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Feb 7, 2017
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Ipsit Gaur
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