Question

Consider the equation 3tan^2(x)−1=0.

the solutions of this equation over the interval {0,pi} are?

Answer 1

3tan^2(x)-1=0
=> 3tan^2(x)=1
=> tan^2(x)=1/3
=> tan(x)= √(1/3) and -√(1/3)
=> x= tan^-1 *(√(1/3)) and tan^-1 *(-√(1/3))