Question

A student has a sample of isopropanol (C3H7OH) that has a mass of 78.6 g. The molar mass of isopropanol is 60.1 g/mol. How many moles of isopropanol are contained in this sample?

Answer 1

The answer is B: 1.31

Step-by-step explanation:

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Answer 2

Given:
mass of isopropanol = 78.6 g
molar mass = 60.1 g/mol

mol isopropanol = mass / molar mass
mol isopropanol = 78.6 g / 60.1 g/mol
mol isopropanol = 1.3078 mol

There is 1.3078 mol isopropanol in the sample.