Question

The Kp for the reaction below is 1.49 × 108 at 100.0 °C:

CO (g) + Cl2 (g) COCl2 (g)

In an equilibrium mixture of the three gases, PCO = PCl2 = 1.00 × 10-4 atm. The partial pressure of the product, phosgene (COCl2), is ________ atm.

Answer 1

The equilibrium constant in this case is [CO2]/[Cl2][CO]. Given the Kp, we can get directly the partial pressure of phosgene which is 1.49x10^8*1x10^-4*1x10^-4. This is equal to 1.49 atm.