Question

In the following reaction, how many grams of oxygen will react with 10.47 grams of benzene (C6H6)? 2C6H6 + 15O2 12CO2 + 6H2O The molar mass of benzene is 78.1074 grams and that of O2 is 32 grams.

Answer 1

32.171087 grams of oxygen will react with 10.47 grams of benzene.

Step-by-step explanation:

`2C_6H_6 + 15O_2\rightarrow 12CO_2 + 6H_2O`

Moles of benzene =
`(10.47 g)/(78.1074 g/mol)=0.1340462 mol`

According to reaction ,2 moles of benzene reacts with 15 moles of oxygen

Then 0.1340462 moles of benzene will react with:

`(15)/(2)* 0.1340462 mol=1.0053464 mol` of oxygen

Mass of 1.0053464 moles of oxygen ;

`1.0053464 mol* 32=32.171087 g`

32.171087 grams of oxygen will react with 10.47 grams of benzene.

Answer 2

The balanced chemical reaction will be:

2C6H6 + 15O2 = 12CO2 + 6H2O We are given the amount of benzene to react with oxygen gas. This will be our starting point. 10.47 g C6H6 ( 1 mol C6H6 / 78.1074 grams C6H6) (15 mol O2/2 mol C6H6 ) ( 32 g O2 / 1 mol O2) = 32.1711g O2