asked 199k views
1 vote
4x^2-x-3=0 solve by completing the square x= ??

1 Answer

5 votes
Hello,

4x²-x-3=0
==>(2x)²-2*1/2*x+1/4-3-1/4=0
==>(2x-1/2)²-13/4=0
==>(4x-1)²-13=0
==>(4x-1-√13)(4x-1+√13)=0
==> x=(1+√13)/4 or x=(1-√13)/4



answered
User Jakub Kriz
by
7.8k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.