Question

What is the molarity of a solution that contains 14.92 grams magnesium chloride in 365 l of solution

Answer 1

Molar mass MgCl₂ = 95.211 g/mol

number of moles => 14.92 / 95.211 = 0.2092 moles

M = n / V

M = 0.2092 / 365

= 5.7315 x 10⁻⁴ M

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