How many grams of CU are required to replace 45.0 grams of silver nitrate? 1Cu + 2AgNO3 -> 1Cu (No3)2 +2Ag

Question

asked Sep 20, 2017 122k views

1 Answer

Esteban Felix · Answer 1 · 2017-09-23T16:45:33+0000

Molar mass Cu = 63.546 g/mol and AgNO₃ = 169.87

1 Cu + 2 AgNO₃ -> 1 Cu (NO₃)₂ +2 Ag

63,546 -------- 2 * 169.87
? g Cu ------- 45.0

Mass ( Cu ) = 45.0 * 63,546 / 2 * 169.87

Mass ( Cu ) = 2859,57 / 339,74

Mass = 8.4169 g of Cu

hope this helps!

How many grams of CU are required to replace 45.0 grams of silver nitrate? 1Cu + 2AgNO3 -> 1Cu (No3)2 +2Ag

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

Related questions

Categories

Other Questions