Question

What is the cube root of 27x^18?

Answer 1

here tell me if u can see the answer I put

Answer 2

Cube root of
`27x^(18)` is
`3x^(6)`

Explanation:

We need to find the cube root of the expression
`27x^(18)`

Take a cube root over
`27x^(18)`

`\sqrt[3]{27x^(18)}`

`\sqrt[3]{3^(3)(x^(6))^(3)}`

simplify the above expression,

`\sqrt[3]{(3x^(6))^(3)}`

`3x^(6)`

Hence, cube root of
`27x^(18)` is
`3x^(6)`