Question

Jose wants to find the perimeter of triangle ABC. He uses the distance formula to determine the length of AC. Finish Jose’s calculations to find the length of AC.

AC=square root<(-2-3)^2 +(6-2)
=square root<(-5)^2+(4)^2

What is the perimeter of triangle ABC? Round the answer to the nearest tenth, if necessary

Answer 1

AC = √[(-2-3)^2 + (6-2)^] = √[5^2 + 4^2] = √[25+16] = √41 =6.4

To find the perimeter you need the lengths of AB and BC.

You already know the points (-2,6) and (3,2)

Then you need the point B to apply the distance formula from B to each of those points.

Answer 2

Given:
AC = √(-2-3)² + (6-2)²
AC = √ -5² + 4²
AC = √ 25 + 16
AC = √41
AC = 6.40

I am assuming that the triangle is an equilateral triangle. This means that all sides are equal.

AC = AB = BC

Perimeter = 6.40 * 3 sides = 19.20