Answer:
In quadrilateral ABCD we have
 AC = AD
 and AB being the bisector of ∠A.
 Now, in ΔABC and ΔABD,
 AC = AD
[Given]
 AB = AB
[Common]
∠CAB = ∠DAB [∴ AB bisects ∠CAD]
 ∴ Using SAS criteria, we have
 ΔABC ≌ ΔABD.
 ∴ Corresponding parts of congruent triangles (c.p.c.t) are equal.
 ∴ BC = BD.