Question

a cooler contains 5 bottles of lemonade 4 bottles of water and 3 bottles of juice each type is equally likely to be chosen based on based on your simulation how many times must a drink be chosen in order to get each type

Answer 1

10 times. I got this answer by adding the 2 biggest numbers, 5 and 4, and in order to get all of them chosen, you need to add at least 1 more drink.

Answer 2

The number of times a drink must be chosen in order to get each type is:

10

Explanation:

It is given that:

a cooler contains 5 bottles of lemonade 4 bottles of water and 3 bottles of juice.

Now we have to choose the maximum number of bottles such that we have got a drink of each type.

Let us suppose at the first 9 draws we did not get any bottle of juice and only got all the bottles of lemonade and water.

Since we know that the sum of 5+4=9

after which at the tenth draw we will definitely get a bottle of juice since all the other drinks were chosen in the previous draw.