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How many factors in the expression 8(x +4) (y +4) (z 2 + 4z + 7) have exactly two terms?
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How many factors in the expression 8(x +4) (y +4) (z 2 + 4z + 7) have exactly two terms?
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Sep 21, 2017
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How many factors in the expression 8(x +4) (y +4) (z 2 + 4z + 7) have exactly two terms?
Mathematics
middle-school
Iulia
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Iulia
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Answer:
I don't know the answer.
Explanation:
I don't know how to solve it either.
Sumitkumar Dhule
answered
Sep 22, 2017
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Sumitkumar Dhule
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3
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From the expression
8(x +4) (y +4) (z 2 + 4z + 7),
the factors are 8, (x+4), (y+4),
(z^2 + 4z + 7) since each of these factors, when you divide that to the whole expression won't give a remainder
Jtolds
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Sep 26, 2017
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Jtolds
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