Question

A ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. What is the final velocity of the ball after 6.0 seconds?

Answer 1

Final velocity v = u + at

Where u = initial velocity = 0, because it was from rest.
a = acceleration = 3.2 m/s²
t = time = 6 seconds

final velocity v = u + at = 0 + 3.2*6 = 0 + 19.2

Final velocity = 19.2 m/s