asked 6.8k views
24 votes
Special right triangles

Special right triangles-example-1
asked
User Ocean
by
7.7k points

2 Answers

6 votes

Answer:

D

Explanation:

Using the cosine ratio in the right triangle and the exact value

cos30° =
(√(3) )/(2) , then

cos30° =
(adjacent)/(hypotenuse) =
(AY)/(RY) =
(AY)/(48) =
(√(3) )/(2) ( cross- multiply )

2AY = 48
√(3) ( divide both sides by 2 )

AY = 24
√(3) → D

answered
User Epik
by
7.9k points
13 votes

Answer:

c

Explanation:

answered
User Chan Le
by
7.4k points

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