Which equation is the inverse of y=2x^2-8

Question

asked Jan 26, 2017 73.4k views

2 Answers

Jesse De Gans · Answer 1 · 2017-01-27T13:10:30+0000

To get the inverse, we should swap the x- and y-variables, then solve for y. Swapping the variables gives the equation:
x=2y^2-8

Solving for y:

$x+8=2y^2 \\ (x+8)/(2)=y^2 \\ y=\sqrt{(x+8)/(2)}$

Dvs · Answer 2 · 2017-02-02T15:12:54+0000

Explanation:

In order to get the inverse of equation, we will interchange the variables and solve for x and y as follows.

y = 2x^(2) - 8

whereas,
y + 8 = 2x^(2)

or x =
$\sqrt{(y+8)/(2)}$

Now, on interchanging the variable we will get the equation as follows.

x = 2y^(2) - 8

x + 8 = 2y^(2)

y =
$\sqrt{(x+8)/(2)}$