Question

Another line passes through the points (-3,-5) and (1,3) find the equation of this line

Answer 1

so slope intercept form
y=mx+b
m=slope
b=y intercept

so slope is found by
(y2-y1)/(x2-x1)
(x,y)
x1=-3
y1=-5
x2=1
y2=3


subsitute
(1-(-5))/(3-(-3))=(1+5)/(3+3)=6/6=1
slope=1
m=1
subsitute
y=1x+b
subsitute one of the points to find b
x=1
y=3
3=1(1)+b
3=1+b
subtract 1
2=b
the equatino is
y=x+2