asked 217k views
1 vote
What is the momentum of a 0.145 kg softball traveling at 10.0 m/s?

2 Answers

4 votes
p=mv=(0.145 kg)*(10.0 m/s) = 1.45 kg*m/s, so it is choice B
answered
User Eligio Becerra
by
8.4k points
3 votes

Answer:

Momentum of the softball, p = 1.45 kg-m/s

Step-by-step explanation:

Given that,

Mass of the softball, m = 0.145 kg

Speed of the ball, v = 10 m/s

We need to find the momentum of the softball. We know that by calculating the product of mass and velocity of the object, we can find its momentum as :


p=m* v


p=0.145\ kg* 10\ m/s

p = 1.45 kg-m/s

So, the momentum of the softball is 1.45 kg-m/s. Hence, this s the required solution.

answered
User Kiranpradeep
by
8.6k points

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