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G(x) = x3 + 6x2 + 12x + 8Determine the function’s value when x = −1. g(−1) = −3 g(−1) = 0 g(−1) = 1 g(−1) = 27

G(x) = x3 + 6x2 + 12x + 8Determine the function’s value when x = −1. g(−1) = −3 g(−1) = 0 g(−1) = 1 g(−1) = 27
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G(x) = x3 + 6x2 + 12x + 8Determine the function’s value when x = −1.

g(−1) = −3

g(−1) = 0

g(−1) = 1

g(−1) = 27

asked
User Leon Timmermans
by
8.7k points

2 Answers

4 votes

Answer:

The Answer is C. 1.

P.S :Love you Guys! hope you get an A+

answered
User Obecker
by
8.5k points
4 votes
Plug in -1 for x and work it ou'

g(-1) = (-1)^3 + 6(-1)^2 + 12(-1) + 8

= -1 + 6 - 12 + 8

= 1
answered
User Chandan Kumar
by
7.9k points
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