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Percent rate of change for the function y=(.94)^x

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\bf \qquad \textit{Amount for Exponential Decay}\\\\ y=I(1 - r)^x\qquad \begin{cases} y=\textit{accumulated amount}\\ I=\textit{initial amount}\\ r=rate\to r\%\to (r)/(100)\\ x=\textit{elapsed time}\\ \end{cases} \\\\\\ y=(0.94)^x\implies y=(1~-~\stackrel{r}{0.06})^x \\\\\\ r=0.06\implies r\%=0.06\cdot 100\implies r=\stackrel{\%}{6}
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