Question

What is the value of the discriminant of the quadratic equation −2x2 = −8x + 8, and what does its value mean about the number of real number solutions the equation has?

The discriminant is equal to 0, which means the equation has no real number solutions.
The discriminant is equal to 0, which means the equation has one real number solution.
The discriminant is equal to 128, which means the equation has no real number solutions.
The discriminant is equal to 128, which means the equation has two real number solutions.

Answer 1

B) The discriminant is equal to 0, which means the equation has one real number solution.

Explanation:

The given equation is -2x^2 = -8x + 8

This can be rewritten as 2x^2 - 8x + 8 = 0

Here the value of a =2, b = -8 and c = 8

Discriminant = b^2 - 4ac

Now plug in the above values in the discriminant, we get

= (-8)^2 - 4*2*8

= 64 - 64

= 0

Here the discriminant is 0, so we will get one real root.

Therefore, the answer B) The discriminant is equal to 0, which means the equation has one real number solution.

Hope this will helpful.

Thank you.

Answer 2

the discriminant is b²-4ac
-2x²+8x-8=0
in this case, b=8, a=-2, c=-8
so b²-4ac=8²-4(-2)(-8)=0
choice B is correct.