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What is the radical form of each of the given expressions?

Drag the answer into the box to match each expression.

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What is the radical form of each of the given expressions? Drag the answer into the-example-1

2 Answers

7 votes

Answer:
5^{(2)/(3)}= \sqrt[3]{5^2}


5^{(1)/(2)}= √(5)


3^{(2)/(5)}= \sqrt[5]{3^2}


3^{(5)/(2)}= √(3^5)


Step-by-step explanation: According to the rule of exponent of radical form:


a^{(m)/(n) } = \sqrt[n]{a^m}.

Let us apply same rule in first number


5^{(2)/(3)}= \sqrt[3]{5^2}


5^{(1)/(2)}= √(5)


3^{(2)/(5)}= \sqrt[5]{3^2}


3^{(5)/(2)}= √(3^5)

Note: When we don't have any number on the top of radical, there 2 is understood.



What is the radical form of each of the given expressions? Drag the answer into the-example-1
answered
User Baxbear
by
8.7k points
4 votes
The main rule to apply here is:

(i)
\displaystyle{ a^ {\displaystyle{ ((b)/(c))} }= \displaystyle{ \sqrt[c]{a^b}

(ii)If c=2, then we write the following
\displaystyle{ a^ {\displaystyle{ ((b)/(2))} }= \displaystyle{ √(a^b).


According to these rules:


\displaystyle{ 5^ {\displaystyle{ ((2)/(3))} }= \displaystyle{ \sqrt[3]{5^2}.


\displaystyle{ 5^ {\displaystyle{ ((1)/(2))} }= \displaystyle{ √(5^1)=\displaystyle{ √(5).


\displaystyle{ 3^ {\displaystyle{ ((2)/(5))} }= \displaystyle{ \sqrt[5]{3^2}.


\displaystyle{ 3^ {\displaystyle{ ((5)/(2))} }= \displaystyle{ √(3^5).
answered
User Dbmikus
by
8.4k points

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