Question

What is the equation of the line that is perpendicular to the line y=1/2x+7 and passes through the point (6,2)

Answer 1

y=1/2x+7, slope is 1/2
perpendicular so slope is opposite and reciprocal
slope = -2
passes through the point (6,2)
y - 2 = -2(x - 6)
y - 2 = -2x + 12
y = -2x + 14

answer
equation y = -2x + 14

Answer 2

Perpendicular lines have slopes that equal
`-1` when they are multiplied. To find the perpendicular slope, set up this equation (let
`x` represent the second equation):


`(1)/(2) (x)=-1`

So,
`x=-2`.

Now, plug in the ordered pair given,
`(6,2)` into the equation
`y=-2x+b` and solve for
`b`.


`2=6(-2)+b`

multiply


`2=-12+b`

add
`12` to both sides


`b=14`

insert the value of
`b` into the equation
`y=-2x+b`

Answer:
`y=-2x+14`

Hope this helps!