Question

The table shows the total number of hamburgers and hot dogs sold at a food stand at a local fair on two separate days. It shows the dollar amount taken in each day. Day 1 : hamburgers sold were 200 hot dogs sold were 150. Total money taken in $1,450. Day 2: hamburgers sold were 200 hot dogs sold were 250. Total money taken in was $1,750. What is the cost of a hamburger and the cost of a hot dog?

Hamburger:
Hot Dog:

Answer 1

The hamburgers are $5 and the hot dogs are $3.

Answer 2

Hamburger: $5.

Hot dog: $3.

Step by step explanation:

We have been given a table that shows the total number of hamburgers and hot dogs sold at a food stand at a local fair on two separate days.

We will form a system of equation from our given information to find the cost of one hamburger and one hot dog.

Let x be price of one hamburger and y be price of one hot dog.

We are told that on first day of fair 200 hamburgers and 150 hot dogs were sold for $1450.

`200x+150y=1450...(1)`

While on second day of fair 200 hamburgers and 250 hot dogs were sold for $1750.

`200x+250y=1750...(2)`

Now we will solve our system of equations by substitution method. From 2nd equation we will get,

`200x=1750-250y`

Now let us substitute this value in 1st equation,

`1750-250y+150y=1450`

`-250y+150y=1450-1750`

`-100y=-300`

`100y=300`

`y=(300)/(100) =3`

Therefore, cost of one hot dog is $3.

Now let us substitute y=3 in equation 1 to find cost of one hamburger.

`200x+(150* 3)=1450`

`200x+450=1450`

`200x=1450-450`

`200x=1000`

`x=(1000)/(200) =5`

Therefore, cost of one hamburger is $5.