asked 189k views
2 votes
What mass will 33.6 l of chlorine gas (cl2) have at stp

asked
User Olliezhu
by
8.1k points

2 Answers

6 votes

Answer:

106 g

Step-by-step explanation:

I took the test

answered
User Mifeet
by
7.8k points
4 votes
The STP stands for standard temperature and pressure which means in a condition where the temperature is 273.15K and the pressure is 0.986atm. In STP, an ideal gas will have a volume 22.4 liters for every mol of gas. Then, the amount of molecule of the 33.6 l of chlorine gas (Cl2) would be:

volume of gas/ number of mol= 22.4l/mol
33.6l/ number of mol= 22.4l/mol
number of mol= 33.6l / (22.4 liters/mol)= 1.5 moles

The mass of the gas would be: 1.5 moles *
70.906 g/mol= 106.359 grams
answered
User Calyth
by
8.1k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.