Question

I have a graphing question

Answer 1

The point slope form of the equation of a straight line is given by


`(y-y_1)=m(x-x_1)`

where
`(x_1,\ y_1)` is a point on the line.

Given


`y-3=(3)/(4)(x+2) \\ \\ y-3=(3)/(4)(x-(-2))`

Thus the line has a slope of 3/4 and passes through the point (-2, 3), we can obtain another point on the line by substituting an arbitrary value for x.

Consider x = 2, then


`y-3= (3)/(4) (2+2)= (3)/(4) (4)=3 \\ \\ \Rightarrow y=3+3=6`

Thus another point on the line is (2, 6).

The line can then be graphed by joining the two points.