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A student did 3 5 of his homework and another 8 problems. then his father came and did one fifth of his homework and the remaining 7 problems. how many problems did they solve t…
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A student did 3 5 of his homework and another 8 problems. then his father came and did one fifth of his homework and the remaining 7 problems. how many problems did they solve t…
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Jan 22, 2018
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A student did 3 5 of his homework and another 8 problems. then his father came and did one fifth of his homework and the remaining 7 problems. how many problems did they solve together?
Mathematics
high-school
CyberMessiah
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Answer:
the ansswer is 75 problems
Explanation:
3/5 x+8 +1/5 x+7=x
x=75
(lets assume x is the student)
Yak
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Jan 23, 2018
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Yak
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Let’s assume the number of problems as P Student did his homework = (3/5) P + 8 Father did the homework = (1/5) P + 7 So the sum of the both equations is equal to P => (3/5) P + 8 + (1/5) P + 7 = P => (4/5) P + 15 = P => 4P + 75 = 5P => P = 75 Problems they solve together are 75 problems.
Roman C
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Jan 26, 2018
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Roman C
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