You throw a 20-n rock vertically into the air from ground level. you observe that when it is a height 16.0 m above the ground, it is traveling at a speed of 24.7 m/s upward.

Question

asked Jun 14, 2018 147k views

1 Answer

Ernesto · Answer 1 · 2018-06-19T21:46:52+0000

The problem is missing some parts. But here are the questions and answers.

a. Use the work-energy theorem to find its speed just as it left the ground

Initial Kinetic Energy = GPE + KE

1/2 * m * V^2 = m * g * h + 1/2 * m * v^2

V^2 = 2 * 9.8 * 15.6 + 25.6^2

=sqrt 968.96

V (initial speed) ≈ 31.130 m/s

b. Use the work-energy theorem to look for its maximum height.

H = 968.96 / 2 * 9.8 ≈ 49.44 m