asked 109k views
5 votes
What is the mass, in grams, of 6.11 mol of sulfur trioxide?

asked
User Brupm
by
8.6k points

2 Answers

3 votes
It would be approximately 489 g, rounded for significant figures. The calculator given answer would be 489.20326. To get that, all you have to do is take your 6.11 moles and multiply it by 80.066 (the molar mass) divided by 1 mol to cancel out the unit.
answered
User Chickens
by
7.3k points
2 votes

Answer : The mass of sulfur trioxide is, 488.8 grams.

Explanation : Given,

Moles of sulfur trioxide = 6.11 mole

Molar mass of sulfur trioxide = 80 g/mole

Formula used :


\text{Mass of }SO_3=\text{Moles of }SO_3* \text{Molar mass of }SO_3

Now put all the given values in this formula, we get the mass of sulfur trioxide.


\text{Mass of }SO_3=6.11mole* 80g/mole=488.8g

Therefore, the mass of sulfur trioxide is, 488.8 grams.

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