Question

What are the zeros of (x^3-5x^2+2x+8)/(x+1)

Answer 1

the roots are 2 and 4
Here is how I did it:
it is hard to factor the numerator, so I used long division, divide the numerator by the denominator, the quotient is x^2-6x+8, which can be factor into (x-2)(x-4)