What is the molarity of the two solutions 0.150 mol of NaOH in 1.80 L of solution

asked Jun 2, 2018 82.0k views

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What is the molarity of the two solutions
0.150 mol of NaOH in 1.80 L of solution

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1 mole of MgS = 24.3 + 32.1 = 56.4 g

35.1 g MgS x 1 mol / 56.4 g = 0.622 mol

M = 0.622 mol / 0.835 L = 0.745 mol/L

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