"how many grams of sucrose (c12h22o11) are in 1.55 l of 0.758 m sucrose solution"

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asked May 12, 2018 179k views

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ConstantineUA · Answer 1 · 2018-05-15T20:37:33+0000

You would use the equation: Molarity M equals amount of solution over volume of solution. So, 0.758 M equals x L divided by 1.55 L OR 0.758 M = x L / 1.55 L . To solve: 1.55 multiplied by 0.758 equals 1.1479. The answer is 1.1479.

"how many grams of sucrose (c12h22o11) are in 1.55 l of 0.758 m sucrose solution"

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