Question

The equation y-2/3=-2(x-1/4) is written in point-slope form. What is the equation in slope-intercept form?

Answer 1

Slope intercept form is given by
y=mx+b

So we want to get the y isolated on the left side.
First distribute the right side
Then add 2/3 to both sides of the equation to get y by itselft.

y-2/3=-2(x-1/4)
y-2/3=-2x+1/2
y=-2x+(3/6+4/6)
y=-2x+10/6
y=-2x+5/3

Answer 2

Answer:
`y=-2x+(7)/(6)`

Explanation:

The slope -intercept form of a line is given by :-

`y=mx+c`

The given equation of a line :
`y-(2)/(3)=-2(x-(1)/(4))`

To convert it into slope-intercept form , we need to multiply -2 inside the brackets , we get

`y-(2)/(3)=-2x-(-2)/(4))\\\\\Rightarrow y-(2)/(3)=-2x+(1)/(2)\\\\\Rightarrow y=-2x+(1)/(2)+(2)/(3)\\\\\Rightarrow\ y=-2x+(7)/(6)`

Hence, the equation in slope-intercept form :
`y=-2x+(7)/(6)`