Question

The sum of three numbers is 62. The second number is equal to the first number diminished by 4. The third number is four times the first. What are the numbers? Which three expressions could be used to represent the numbers? n; n - 4; 4n n; 4 - n; n + 4 n; n/4; n + 4

Answer 1

n = first number
2nd number = n diminished by 4.....n - 4
3rd number is 4 times the first.....4n

ur 3 expressions are : n , n - 4, 4n <==

Answer 2

Numbers: 11, 7 and 44

Expressions: n, n - 4, 4n

Explanation:

We have that A + B + C = 62, where A, B and C represent numbers.

We know that the 2nd number (B) is equal to the first number (A), diminished by 4. This means B = A - 4

We also know that the 3rd number (C) is four times the first (A), that is to say 4*A. This means C = 4*A

If we replace this information in the first expression, we have

A + B + C = A + (A - 4) + (4*A) = 62

We change an equation of 3 variables to an equation of just one. Now we solve it putting together the terms that have the variable A:

A + A - 4 + 4*A = 62

2A + 4A - 4 + 4 = 62 + 4

6A = 66

A = 11

Our first number is 11, now we find B and C:

B = A - 4 = 11 - 4 = 7

C = 4A = 4*11 = 44

So, the numbers are 11, 7 and 44

If we change the A for a "n", the expressions that represent the numbers are n, n - 4 and 4n