If there are 10.0 g of sucrose and 8.0 g of oxygen, how many moles of sucrose are available for this reaction? A.) 0.029 mol B.) 0.250 mol C.) 0.351 mol D.) 3.00 mol

Question

asked Feb 19, 2018 164k views

2 Answers

Martin Dreher · Answer 1 · 2018-02-22T22:23:07+0000

Answer: A.) 0.029

Explanation: To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\textMolar mass}}$

For sodium:

Mass of sucrose given = 10 g

Molar mass of sucrose
C_(12)H_(22)O_(11) = 342 g/mol

Putting values in above equation, we get:

$\text{Moles of sodium}=(10g)/(342g/mol)=0.029mol$

Thus the number of moles of sucrose available for this reaction will be 0.029.