An investment is currently worth 1.035×108 dollars . Thirty years ago, the investment was worth 2.3×105 dollars. How many times greater is the value of the investment today …

Question

asked Mar 20, 2018 43.9k views

2 Answers

Shanda · Answer 1 · 2018-03-22T22:07:55+0000

Answer: B. 450

Explanation:

Given: An investment is currently worth =
1.035*10^8 dollars .

Thirty years ago, the investment was worth =
2.3*10^5 dollars.

Now, the number of times the value of the investment today than the value of the investment thirty years ago is given by :-

$n=(1.035*10^8)/(2.3*10^5)\\\\=0.45*10^(8-5)........\text{Since }a^na^m=a^(m+n)\\\\=0.45*10^3\\\\=0.45*1000=450$

Hence, the value of the investment today is 450 times greater than the value of the investment thirty years ago.

Petko Kamenov · Answer 2 · 2018-03-25T03:38:10+0000

The correct option is: B. 450

Explanation

Current value of the investment is
1.035* 10^8 dollars and 30 years ago, the value of the investment was
2.3* 10^5 dollars.

Suppose, the value of investment today is
times greater than the value of the investment thirty years ago.

So, the equation will be........

$n(2.3* 10^5)=1.035* 10^8\\ \\ n= (1.035* 10^8)/(2.3* 10^5)=0.45* 10^3 = 450$

Thus, the value of the investment today is 450 times greater than the value of the investment thirty years ago.