Calculate the number of Kilojoules to warm 125 g of iron from 23.5 C to 78.0 C

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asked Jun 2, 2018 17.3k views

2 Answers

Trann · Answer 1 · 2018-06-08T09:35:44+0000

We know that
M = 125 g = 125/1000 kg = 0.125 kg,
θ₂ = 78.0°C
θ₁ = 23.5°C ,
c = 0.44kJ/kg°C,

the number of Kilojoules to warm the iron would be

Q = mc(θ₂ - θ₁)

Q = 0.125*0.440*(78 - 23.5)

Q = 2.9975 kJ

2.9975 kJ required to warm it.

Calculate the number of Kilojoules to warm 125 g of iron from 23.5 C to 78.0 C

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