What is the empirical formula of the phosphorus selenide?

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asked Jul 7, 2018 14.3k views

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Leerob · Answer 1 · 2018-07-11T07:35:16+0000

atomic mass of phosphorous = 31g atomic mass of selenium = 79g 45.2/31 = 1.45 which is nearly 1.5 mol of P 131.6 - 45.2 = 86.4g 86.4/79 =1.09 which is nearly 1 mol of Se So the empirical formula of the phosphorus selenide is: P3Se2

What is the empirical formula of the phosphorus selenide?

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