Answer:
Second set.
Explanation:
I put the formula of standart deviation in the image below. 
x is each data of the list
μ is the data average
N is the amount of elements.
So, for the first list we have:
μ= 

DE= 

= 

= 

= 

= 5879.1061.
For the other list of elements:
μ= 

DE=
![\sqrt^(2))/(6)]()
= 

= 

= 

= 6029.32
Then, the second set is more variable.