asked 229k views
2 votes
What is the solution for the equation 5/3b^3-2b-5=2/b3-2

A. b= -4 and b= 0
B. b= -4
C. b= 0 and b= 4
D. b= 4

asked
User Colymba
by
7.8k points

2 Answers

5 votes

Answer:

c

Explanation:

answered
User Abhay Dixit
by
8.3k points
0 votes

Answer:

Option C is correct.

Explanation:

Given Equation:


(5)/(3b^3-2b^2-5)=(2)/(b^3-2)

To find: Solution of the Equation.

Consider,


5(b^3-2)=2(3b^3-2b^2-5)


5b^3-10=6b^3-4b^2-10


6b^3-5b^3-4b^2+10-10=0


b^3-4b^2=0


b^2(b-4)=0

b² = 0 ⇒ b = 0

b - 4 = 0 ⇒ b = 4

Therefore, Option C is correct.

answered
User Pravnar
by
7.6k points
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