Question

The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?

a.No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64
b.No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32
c.Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64
d.Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32

Answer 1

B. No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32

Perimeter = 2(l + w)
Perimeter = 64

Assuming: P = 64; w = 11 ; l = ?
64 = 2(l + 11)
64/2 = l + 11
32 - 11 = l
length = 21.