Answer:
d = 26 .5
Explanation:
Given : circle with two secant.
To find : what is the value of d to the nearest tenth.
Solution : We have given a circle with two secant.
By the theorem :
If two secants are drawn to a circle from an external point of the circle then the product of one secant (length) and its external part is equal to the product of other secant and its external part.
Then ,
22 × (22 + 40) = 26 × ( 26 + d ).
22 * 62 = 26 * ( 26+ d).
1364 = 26 ( 26 + d ) .
on dividing both side by 26
= ( 26 + d ) .
52.5 = 26 +d
On subtracting both side
52.5 - 26 = d
26 .5 = d.
Therefore , d = 26 .5