Question

How many hydrogen atoms are present in 0.70 moles of ptcl2(nh3)2?

Answer 1

To find the number of hydrogen atoms in 0.70 moles of PtCl2(NH3)2, multiply 0.70 moles by 6 hydrogen atoms per molecule and by Avogadro's number, resulting in 2.51 × 10^24 hydrogen atoms.

Step-by-step explanation:

To calculate the number of hydrogen atoms in 0.70 moles of PtCl2(NH3)2, you first need to understand the composition of the compound. Each molecule of PtCl2(NH3)2 contains two ammonia molecules (NH3), which means there are a total of two nitrogen atoms and six hydrogen atoms.

Using Avogadro's number, which states that one mole of any substance contains approximately 6.02 × 1023 entities (atoms, molecules, etc.), we can calculate the total number of hydrogen atoms in 0.70 moles of the compound:

0.70 moles × 6 hydrogen atoms/molecule × 6.02 × 1023 atoms/mole = 2.51 × 1024 hydrogen atoms.

Answer 2

In this case, the hydrogen atoms are present in the (NH3)2 part of the molecule. The sign (NH3)2 mean that there are two NH3 molecules in their compound. That means the total atom of hydrogen would be: 3*2 = 6 atom for every compound molecule
Since there is 0.7 mole of compound, then the hydrogen atom would be:
0.7 mole * 6= 4.2 moles