-3a^2 (4a^3-3a+2a^4)

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asked Apr 1, 2018 57.7k views

1 Answer

Charles Williams · Answer 1 · 2018-04-06T06:21:46+0000

-6a^6 - 12a^5 +9a^3 Is the answer

-3a^2 (4a^3-3a+2a^4) You distribute -3a^2

-3a^2 X 4a^3 = -12a^5

-3a^2 X -3a = 9a^3

-3a^2 X 2a^4 = -6a^6

You would order this in so the highest exponent is in the front
-6a^6 - 12a^5 +9a^3

-3a^2 (4a^3-3a+2a^4)

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