Question

Use the periodic to fill in the numbers in the electron configurations shown below. B: 1s2 2sA2pB

Answer 1

The answer is

A= 2

B= 1

Answer 2

Step-by-step explanation:

Atomic number of boron is 5 and its electronic configuration is
`1s^(2)2s^(2)2p^(1)`. Boron is a non-metal and belongs to group 13.

That is, 2s shell of boron atom contains 2 electrons and 2p shell of the atom has 1 electron.

Therefore, we can conclude that the value of A equals 2 and value of B equals 1 in B: 1s2 2sA2pB.