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What is the center and radius of the circle with equation x2 + y2 - 4x + 22y + 61 = 0?

What is the center and radius of the circle with equation x2 + y2 - 4x + 22y + 61 = 0?
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What is the center and radius of the circle with equation x2 + y2 - 4x + 22y + 61 = 0?

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User Papooch
by
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1 Answer

5 votes
Hello,


x^2+y^2-4x+22y+61=0\\\\ (x^2-4x+4) +(y^2+22y+121)-121-4+61=0\\\\ (x-2)^2+(y+11)^2=64

Center is (2,-11) and radius is 8
answered
User Mitzie
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