Question

find three consecutive even integers. such that 7 times of first integer is 14 more than the sum of second and third integers.

Answer 1

Let the even number be 2n, 2n+2, 2n+4 where n=1,2,3,....

Given Condition is

7(2n)=(2n+2+2n+4)+14

14n=4n+6+14

14n-4n=20

10n=20

n=20/10

n=2

So the Numbers are 2x2, 2x2+2, 2x2+4

Answer is 4,6,8